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exam algebra 2 cp 1. solve this system of equations: \\( y = -4x + 13 \…

Question

exam algebra 2 cp 1. solve this system of equations: \\( y = -4x + 13 \\) \\( y = \frac{1}{2}x + 4 \\) a. \\( (2, -5) \\) b. \\( (-2, 5) \\) c. \\( (2, 5) \\) 2. what is the correct \\( 1^{st} \\) step to solve this system of equations? \\( 2x + 3y = 9 \\) \\( 2x - 5y = 3 \\) a. add them b. subtract them c. multiply \\( 1^{st} \\) equation by 5 3. select the coordinate point that is a solution to the following system. \\( -4x + 3y = -16 \\) \\( x - 5y = -13 \\) a. \\( (4, 7) \\) b. \\( (7, -7) \\) c. \\( (7, 4) \\) 4. spongebob is a ________. a. sponge b. robert c. moose 5. if you were using substitution to solve the following system, what is the result of the \\( 1^{st} \\) step? \\( y = 4x - 5 \\) \\( y = 2x + 3 \\) a. \\( 4x + y = -5 \\) b. \\( 4x - 5 = 2x + 3 \\) c. \\( y = 2(4x - 3) - 5 \\) 6. the answer to \\( 2x + 14 > 8 + 2x \\) is? a. many solutions b. no solution c. \\( -6 \\) 7. indicate the incorrect step. \\( 2x + 4 - x = 19x - 11 \\) step 1: \\( x + 4 = 19x - 11 \\) step 2: \\( \div 19x \\) \\( \div 19x \\) a. step 1 b. step 2 c. stepson

Explanation:

Question 1

Step1: Set equations equal

Since both equal \( y \), set \( -4x + 13=\frac{1}{2}x + 4 \).

Step2: Solve for \( x \)

Add \( 4x \) to both sides: \( 13=\frac{9}{2}x + 4 \). Subtract 4: \( 9=\frac{9}{2}x \). Multiply by \( \frac{2}{9} \): \( x = 2 \).

Step3: Find \( y \)

Substitute \( x = 2 \) into \( y=-4x + 13 \): \( y=-8 + 13 = 5 \). So solution is \( (2,5) \).

The system is \( 2x + 3y = 9 \) and \( 2x - 5y = 3 \). The \( x \)-coefficients are both 2. Subtracting the equations (or subtracting the second from the first) will eliminate \( x \), which is a common first step for elimination. Adding would not eliminate \( x \), and multiplying by 5 is not needed here.

Step1: Solve the second equation for \( x \)

From \( x - 5y=-13 \), we get \( x = 5y - 13 \).

Step2: Substitute into first equation

Substitute \( x = 5y - 13 \) into \( -4x + 3y=-16 \): \( -4(5y - 13)+3y=-16 \).

Step3: Simplify and solve for \( y \)

\( -20y + 52 + 3y=-16 \) → \( -17y=-68 \) → \( y = 4 \).

Step4: Find \( x \)

Substitute \( y = 4 \) into \( x = 5y - 13 \): \( x = 20 - 13 = 7 \). So solution is \( (7,4) \).

Answer:

c. (2,5)

Question 2