Question

every person has one of eight blood types, determined by molecules on the surface of their red blood cells. individuals can only receive specific blood types, usually the one that matches their own. use the circle graph showing the percentage of individuals with each blood type to answer parts a and b.

a. what are the odds in favor of randomly selecting an individual with blood type o-negative?
the odds in favor of selecting an individual with blood type o-negative are \boxed{\frac{\quad}{\quad}}.
(simplify your answers.)

blood types in a certain country
\

$$\begin{tabular}{|c|c|c|c|c|c|c|c|} \\hline \\text{o-positive} & \\text{a-positive} & \\text{b-positive} & \\text{o-negative} & \\text{a-negative} & \\text{ab-negative} & \\text{b-negative} & \\text{ab-positive} \\\\ \\hline 38\\% & 35\\% & 9\\% & 6\\% & 5\\% & 4\\% & 2\\% & 1\\% \\\\ \\hline \\end{tabular}$$

Explanation:

Step1: Find the probability of success and failure

The probability of selecting an individual with blood type O - negative (\(P(\text{success})\)) is \(6\%\) or \(0.06\). The probability of not selecting an individual with blood type O - negative (\(P(\text{failure})\)) is \(100\% - 6\%=94\%\) or \(0.94\).

Step2: Calculate the odds

The formula for odds in favor is \(\text{Odds}=\frac{P(\text{success})}{P(\text{failure})}\). Substitute \(P(\text{success}) = 0.06\) and \(P(\text{failure})=0.94\) into the formula: \(\text{Odds}=\frac{0.06}{0.94}=\frac{6}{94}=\frac{3}{47}\)

Answer:

\(3:47\)