Question

evaluate the function at the given value of the variable.
$f(x)=4x^{2}-4$
a. $f(6)$
b. $f(-4)$

a. $f(6)= 140$

b. $f(-4)=\square$

Explanation:

Step1: Substitute x = -4 into the function

We have the function \( f(x) = 4x^2 - 4 \). Substitute \( x = -4 \) into it, so we get \( f(-4)=4\times(-4)^2 - 4 \).

Step2: Calculate the exponent first

According to the order of operations (PEMDAS/BODMAS), we calculate the exponent first. \( (-4)^2 = 16 \), so the expression becomes \( f(-4)=4\times16 - 4 \).

Step3: Perform the multiplication

Calculate \( 4\times16 = 64 \), so now we have \( f(-4)=64 - 4 \).

Step4: Perform the subtraction

Subtract 4 from 64: \( 64 - 4 = 60 \).

Answer:

60