Question

ero math 1 - unit 5
\\(\frac{4x^{2}}{-2x^{-3}y^{-2}}\\)
8

Explanation:

Step1: Simplify coefficients

Simplify the coefficient $\frac{4}{-2} = -2$.

Step2: Simplify $x$ terms

Using the rule $x^m \div x^n = x^{m - n}$, for $x$ terms: $x^2 \div x^{-3} = x^{2 - (-3)} = x^{5}$.

Step3: Simplify $y$ terms

Using the rule $y^m \div y^n = y^{m - n}$, for $y$ terms: $y^{0} \div y^{-2}$ (since there's no $y$ in numerator, assume $y^0$) $= y^{0 - (-2)} = y^{2}$.

Step4: Combine all parts

Multiply the simplified coefficient, $x$ term, and $y$ term: $-2 \times x^{5} \times y^{2} = -2x^{5}y^{2}$.

Answer:

$-2x^{5}y^{2}$