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5. in the equation below, fill in the blank with the slope of your grap…

Question

  1. in the equation below, fill in the blank with the slope of your graph. if necessary, make corrections to your paper analysis question 3.
y=mx+b
dependent variable=slopeindependent variable+vertical intercept
weight=? n/kgmass+0 (or very close to 0)
  1. slope meaning: the slope is ____ newtons per kilogram. this means that for every __ kg of mass, the weight of an object increases by ____ n.
  1. what does this equation mean?

to calculate an objects weight, you multiply the objects mass by _____, and then add _____.

Explanation:

Step1: Recall the relationship between weight and mass

The formula relating weight (\(W\)) and mass (\(m\)) is \(W = mg\), where \(g\) is the acceleration due to gravity (slope here) with a value of approximately \(9.8\space N/kg\) (or \(10\space N/kg\) for approximate calculations).

Step2: Analyze the equation structure

The given equation is \(weight = m\times mass + b\), with \(b\approx0\). So the slope \(m\) should be the acceleration due to gravity, \(9.8\space N/kg\) (or \(10\space N/kg\)). For the slope meaning: The slope is \(9.8\) (or \(10\)) Newtons per kilogram. This means that for every \(1\space kg\) of mass, the weight of an object increases by \(9.8\) (or \(10\)) \(N\). For the last part (question 7), to calculate weight, multiply mass by the slope (acceleration due to gravity, \(9.8\) or \(10\space N/kg\)) and add \(0\) (since \(b = 0\)).

Answer:

(for question 5 slope, question 6, and question 7):

  • Question 5: The slope (m) is \(\boldsymbol{9.8}\) (or \(\boldsymbol{10}\)) \(N/kg\).
  • Question 6: The slope is \(\boldsymbol{9.8}\) (or \(\boldsymbol{10}\)) Newtons per kilogram. This means that for every \(\boldsymbol{1}\) \(kg\) of mass, the weight of an object increases by \(\boldsymbol{9.8}\) (or \(\boldsymbol{10}\)) \(N\).
  • Question 7: To calculate an object's weight, you multiply the object's mass by \(\boldsymbol{9.8\space N/kg}\) (or \(\boldsymbol{10\space N/kg}\)), and then add \(\boldsymbol{0}\).