Question

draw the lewis electron dot structure for h₂s. what is the vsepr shape of the particle? linear tetrahedral trigonal planar bent

Explanation:

Step1: Determine the central atom

In \(H_2S\), sulfur (\(S\)) is the central atom as it has a lower electronegativity than hydrogen (\(H\)).

Step2: Calculate the number of valence electrons

Hydrogen has \(1\) valence electron, and sulfur has \(6\) valence electrons. For \(H_2S\), the total number of valence electrons is \(2\times1 + 6=8\).

Step3: Draw the Lewis structure

Sulfur forms single bonds with two hydrogen atoms. After bonding, sulfur has two lone pairs of electrons.

Step4: Determine the VSEPR shape

Using the VSEPR theory, for \(H_2S\), the steric number (number of bonding pairs + number of lone pairs) is \(2 + 2=4\). The electron - pair geometry is tetrahedral. But considering the molecular shape (ignoring lone pairs for the final shape description in terms of atoms), the shape of \(H_2S\) is bent.

Answer:

bent