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distance formula: part 1 1 more question to go which of the following w…

Question

distance formula: part 1
1 more question to go
which of the following would be an incorrect way to substitute the points (2,3) and (-4, -3) into the distance formula?
○ $\sqrt{(-4 - 2)^2 + (3 - 3)^2}$
○ $\sqrt{(2 - 4)^2 + (3 - 3)^2}$
○ $\sqrt{(2 - (-4))^2 + (3 - (-3))^2}$
○ two of these are incorrect.
submit

Explanation:

The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\) (or equivalently \(\sqrt{(x_1 - x_2)^2+(y_1 - y_2)^2}\) since squaring eliminates the sign difference).

Step 1: Analyze the first option

For points \((2,3)\) (let \(x_1 = 2,y_1 = 3\)) and \((- 4,-3)\) (let \(x_2=-4,y_2 = - 3\)), the first option is \(\sqrt{(-4 - 2)^2+(3 - 3)^2}\). Here, \(x_2 - x_1=-4 - 2\) and \(y_2 - y_1=3 - 3\) (wait, \(y_2=-3\), so \(y_2 - y_1=-3 - 3=-6\), but in the first option \(y_2 - y_1\) is written as \(3 - 3\) which is wrong. Wait, no, maybe we swapped \(x_1,y_1\) and \(x_2,y_2\). If we take \((x_1=-4,y_1 = - 3)\) and \((x_2 = 2,y_2=3)\), then \(x_2 - x_1=2-(-4)=6\), \(y_2 - y_1=3-(-3) = 6\). But the first option has \(x_2 - x_1=-4 - 2=-6\) (squaring will make it \(36\)) and \(y_2 - y_1=3 - 3 = 0\) (which is wrong because \(y_2 - y_1\) should be \(3-(-3)=6\) or \(-3 - 3=-6\)). Wait, no, let's re - evaluate.

Wait, the first option: \(\sqrt{(-4 - 2)^2+(3 - 3)^2}\). Let's check the \(y\) - component. The \(y\) - coordinates of the points are \(3\) and \(-3\). So \(y_2 - y_1\) should be either \(3-(-3)=6\) or \(-3 - 3=-6\), but in the first option, it is \(3 - 3 = 0\), which is incorrect.

Step 2: Analyze the second option

The second option is \(\sqrt{(2 - 4)^2+(3 - 3)^2}\). The \(x\) - coordinates of the given points are \(2\) and \(-4\), not \(2\) and \(4\). So the \(x\) - component \(2 - 4\) is incorrect (it should be \(2-(-4)\) or \(-4 - 2\)) and the \(y\) - component \(3 - 3\) is also incorrect (should be \(3-(-3)\) or \(-3 - 3\)).

Step 3: Analyze the third option

The third option is \(\sqrt{(2-(-4))^2+(3 - (-3))^2}\). Using the distance formula with \((x_1 = 2,y_1 = 3)\) and \((x_2=-4,y_2=-3)\), \(x_2 - x_1=-4 - 2=-6\), \(x_1 - x_2=2-(-4)=6\) (since \((x_1 - x_2)^2=(x_2 - x_1)^2\)) and \(y_2 - y_1=-3 - 3=-6\), \(y_1 - y_2=3-(-3)=6\) (since \((y_1 - y_2)^2=(y_2 - y_1)^2\)). So this substitution is correct.

Step 4: Analyze the fourth option

Since the first and the second options are incorrect, the statement "Two of these are incorrect" is correct? Wait, no, wait. Wait, the first option: \(\sqrt{(-4 - 2)^2+(3 - 3)^2}\). Let's recalculate the \(y\) - difference. The two points are \((2,3)\) and \((-4,-3)\). The \(y\) - difference is \(3-(-3)=6\) or \(-3 - 3=-6\). In the first option, the \(y\) - difference is \(3 - 3 = 0\), which is wrong. The second option: \(\sqrt{(2 - 4)^2+(3 - 3)^2}\). The \(x\) - difference should be \(2-(-4)\) or \(-4 - 2\), not \(2 - 4\), and the \(y\) - difference is wrong. The third option is correct. So the first and the second are incorrect, so the option "Two of these are incorrect" is correct? Wait, no, the question is "Which of the following would be an incorrect way...". Wait, let's re - express the distance formula.

The distance formula is \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). Let's take \((x_1 = 2,y_1 = 3)\) and \((x_2=-4,y_2=-3)\).

  • First option: \(\sqrt{(-4 - 2)^2+(3 - 3)^2}\). Here, \(x_2 - x_1=-4 - 2=-6\) (correct, since \(x_2=-4,x_1 = 2\)), but \(y_2 - y_1=-3 - 3=-6\), but in the formula, it is \(3 - 3 = 0\) (wrong).
  • Second option: \(\sqrt{(2 - 4)^2+(3 - 3)^2}\). \(x_2\) is \(-4\), not \(4\), so \(x_1 - x_2=2-(-4)=6\), not \(2 - 4=-2\) (wrong), and \(y_2 - y_1\) is wrong as above.
  • Third option: \(\sqrt{(2-(-4))^2+(3 - (-3))^2}\). \(x_1 - x_2=2-(-4)=6\), \(y_1 - y_2=3-(-3)=6\), which is correct (since \((x_1 - x_2)^2=(x_2 - x_1)^2\) and \((y_1 - y_2)^2=(y_2 - y_1)^2\)).

So the first option has a wrong \(y\) - component, the…

Answer:

Two of these are incorrect.