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diagonal vs. perimeter here is some of the data that you and your class…

Question

diagonal vs. perimeter
here is some of the data that you and your classmates collected
about squares with different diagonal lengths.
diagonal length (toothpicks) perimeter (toothpicks)
1 2.83
2 5.66
3 8.49
4 11.32
5 14.15
a. discuss: is the relationship between diagonal length and
perimeter proportional? how do you know?
b. how can you estimate the perimeter of a square with a
diagonal of 100 toothpicks?

Explanation:

a.

Brief Explanations

To check for proportionality, we use the formula for proportionality \(y = kx\), where \(k\) is the constant of proportionality. Let \(x\) be the diagonal length and \(y\) be the perimeter.
For \(x = 1,y=2.83\), then \(k=\frac{y}{x}=\frac{2.83}{1}=2.83\)
For \(x = 2,y = 5.66\), then \(k=\frac{y}{x}=\frac{5.66}{2}=2.83\)
For \(x = 3,y=8.49\), then \(k=\frac{y}{x}=\frac{8.49}{3}=2.83\)
For \(x = 4,y = 11.32\), then \(k=\frac{y}{x}=\frac{11.32}{4}=2.83\)
For \(x = 5,y=14.15\), then \(k=\frac{y}{x}=\frac{14.15}{5}=2.83\)

Since the ratio \(\frac{\text{Perimeter}}{\text{Diagonal length}}\) (i.e., \(k\)) is constant (\(k = 2.83\)), the relationship between diagonal length and perimeter is proportional.

b.

Brief Explanations

Since the relationship is proportional with \(k = 2.83\) (from part a), and the formula for the relationship is \(y=kx\) (where \(y\) is perimeter and \(x\) is diagonal length).
When \(x = 100\) (diagonal length), we substitute \(x\) into the equation \(y=kx\).
So, \(y=2.83\times100\)

Answer:

a. The relationship is proportional. Because \(\frac{\text{Perimeter}}{\text{Diagonal length}}\) is a constant (\(2.83\)).
b. Estimate the perimeter as \(2.83\times100 = 283\) toothpicks.