Question

a deck of uno cards has 4 colors (suits): red, yellow, green, blue
each color has cards numbered 1 to 9,
so the total number of these cards = 4*9 = 36
(an uno deck also has other, special cards, but for this question, those special cards are removed for the
deck. only the numbered cards are used.)
a) event e = randomly selecting an uno card that is red.
what is the probability of event e?
\\(\frac{9}{36}\\) \\(\quad\\) (enter a fraction; it does not have to be reduced.)

b) event f = randomly selecting an uno card that is some number from 1 to 4 of any of the 4 colors.
what is the probability of event f?
\\(\frac{16}{36}\\) \\(\quad\\) (enter a fraction; it does not have to be reduced.)

c) how many cards are in the intersection of events e and f? 4

d) p(e and f) = the probability of choosing a card in the intersection of events e and f: p(e and f) = ?
\\(\frac{4}{36}\\)

e) let event g = e or f.use the general addition rule to compute p(g): p(g) = p(e) + p(f) - p(e and f)
\\(\frac{21}{36}\\)

f) how many cards are in event g? \\(\square\\)

Explanation:

Step1: Recall Probability and Counting

We know that \( P(G)=\frac{21}{36} \) from part (e), and the total number of cards is 36. The number of cards in event \( G \) can be found by using the formula \( P(G)=\frac{\text{Number of cards in } G}{\text{Total number of cards}} \). Let \( n \) be the number of cards in \( G \). Then \( \frac{n}{36}=\frac{21}{36} \).

Step2: Solve for \( n \)

Multiply both sides of the equation \( \frac{n}{36}=\frac{21}{36} \) by 36. We get \( n = 21 \).

Answer:

21