Question

a cylinder has a base diameter of 18 meters and a height of 17 meters. what is its volume in cubic meters, to the nearest tenths place?
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answer attempt 2 out of 2

Explanation:

Step1: Find the radius of the base

The diameter \( d = 18 \) meters, so the radius \( r=\frac{d}{2}=\frac{18}{2} = 9 \) meters.

Step2: Recall the volume formula for a cylinder

The volume \( V \) of a cylinder is given by the formula \( V=\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height.

Step3: Substitute the values of \( r \) and \( h \) into the formula

We know \( r = 9 \) meters and \( h=17 \) meters. So \( V=\pi\times(9)^{2}\times17=\pi\times81\times17 = 1377\pi \)

Step4: Calculate the numerical value and round to the nearest tenths

Using \( \pi\approx3.14159 \), we have \( V\approx1377\times3.14159\approx4324.7 \) (rounded to the nearest tenths place)

Answer:

\( 4324.7 \)