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construct the equation of the regression line. an editing firm compiled…

Question

construct the equation of the regression line.

an editing firm compiled the following table which lists the number of pages contained in a piece of technical writing and the cost of proofreading and correcting them (in dollars). assume there is a significant linear relationship between x and y and construct the equation of the linear regression line.

number of pages vs cost

number of pages, x7124142530

note: r=0.9999

  • ŷ = 15.4(x) + 7.1
  • ŷ = 7.1(x) + 15.4
  • ŷ = 1.6(x) + 17.9
  • ŷ = 17.9(x) + 1.6

Explanation:

Step1: Calculate mean of x and y

First, find the mean of \( x \) (number of pages) and \( y \) (cost).
For \( x \): \( \bar{x} = \frac{7 + 12 + 4 + 14 + 25 + 30}{6} = \frac{92}{6} \approx 15.333 \)
For \( y \): \( \bar{y} = \frac{128 + 213 + 75 + 250 + 446 + 540}{6} = \frac{1652}{6} \approx 275.333 \)

Step2: Calculate slope (m)

The slope \( m \) of the regression line can also be estimated by checking which option passes near \( (\bar{x}, \bar{y}) \). Let's test each option:

  • Option 1: \( \hat{y} = 15.4x + 7.1 \). At \( x \approx 15.333 \), \( \hat{y} = 15.4(15.333) + 7.1 \approx 236.13 + 7.1 \approx 243.23 \) (not close to 275.33)
  • Option 2: \( \hat{y} = 7.1x + 15.4 \). At \( x \approx 15.333 \), \( \hat{y} = 7.1(15.333) + 15.4 \approx 108.86 + 15.4 \approx 124.26 \) (no)
  • Option 3: \( \hat{y} = 1.6x + 17.9 \). At \( x \approx 15.333 \), \( \hat{y} = 1.6(15.333) + 17.9 \approx 24.53 + 17.9 \approx 42.43 \) (no)
  • Option 4: \( \hat{y} = 17.9x + 1.6 \). At \( x \approx 15.333 \), \( \hat{y} = 17.9(15.333) + 1.6 \approx 274.46 + 1.6 \approx 276.06 \), which is very close to \( \bar{y} \approx 275.33 \).

Answer:

\( \hat{y} = 17.9(x) + 1.6 \)