Question

consider the reaction.
n₂(g) + 3h₂(g) ←→ 2nh₃(g)
at equilibrium, the concentrations of the different species are as follows.
nh₃ = 0.105 m
n₂ = 1.1 m
h₂ = 1.50 m
what is the equilibrium constant for the reaction at this temperature?

Explanation:

Step1: Escribir la expresión de la constante de equilibrio

Para la reacción \(N_{2}(g)+3H_{2}(g)\longleftrightarrow2NH_{3}(g)\), la constante de equilibrio \(K_{c}\) está dada por la fórmula \(K_{c}=\frac{[NH_{3}]^{2}}{[N_{2}][H_{2}]^{3}}\)

Step2: Sustituir los valores de concentración

Sustituimos \([NH_{3}]=0.105\space M\), \([N_{2}]=1.1\space M\) y \([H_{2}]=1.50\space M\) en la fórmula:

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Answer:

0.0030