Question

consider an element with the following ionization energy values. ie₁: 786; ie₂: 1580; ie₃: 3230; ie₄: 4360; ie₅: 6270; ie₆: 22200 how many v.e. does the element have?

Explanation:

Step1: Analyze the ionization energy jumps

Ionization energy ($IE$) is the energy required to remove an electron from an atom. A large jump in $IE$ occurs when a core electron is being removed. Core electrons are more tightly bound to the nucleus compared to valence electrons.

Step2: Identify the large jump

Looking at the given $IE$ values: $IE_1 = 786\ kJ/mol$, $IE_2=1580\ kJ/mol$, $IE_3 = 3230\ kJ/mol$, $IE_4=4360\ kJ/mol$, $IE_5 = 6270\ kJ/mol$, $IE_6=22200\ kJ/mol$.
The largest jump is between $IE_5$ and $IE_6$. This indicates that after removing 5 electrons (valence electrons), the sixth electron is a core electron.

Answer:

The element has 5 valence electrons.