Question

a common chemical reaction involves two ionic compounds that exchange ions to form two new compounds. the reactants and products for one of these reactions are given below.
reactants: potassium sulfate and barium nitrate
products: barium sulfate and potassium nitrate
which of the following shows the correct formulas for the reactants?
choose 1 answer:

k₂so₄ + ba(no₃)₂

k₂s + ba(no₃)₂

kso₄ + bano₃

k₂s + bano₃

which of the following shows the correct formulas for the products?
choose 1 answer:

bas + k₂no₃

baso₄ + kno₄

so₄ba + no₄k

baso₄ + k₂(no₄)₂

Explanation:

• For reactants:
• Potassium sulfate: Potassium (\(K^+\)) has a charge of \(+1\), sulfate (\(SO_4^{2 -}\)) has a charge of \(- 2\). To balance the charges, we need \(2\) \(K^+\) ions for each \(SO_4^{2 -}\) ion. So the formula is \(K_2SO_4\).
• Barium nitrate: Barium (\(Ba^{2+}\)) has a charge of \(+2\), nitrate (\(NO_3^-\)) has a charge of \(-1\). To balance the charges, we need \(2\) \(NO_3^-\) ions for each \(Ba^{2+}\) ion. So the formula is \(Ba(NO_3)_2\).
• For products:
• Barium sulfate: Barium (\(Ba^{2+}\)) and sulfate (\(SO_4^{2 -}\)) combine in a \(1:1\) ratio (since \(+2+(-2) = 0\)). So the formula is \(BaSO_4\).
• Potassium nitrate: Potassium (\(K^+\)) and nitrate (\(NO_3^-\)) combine in a \(1:1\) ratio (since \(+1+(-1)=0\)). So the formula is \(KNO_3\).

Answer:

• Reactants: \(K_2SO_4 + Ba(NO_3)_2\) (first option for reactants)
• Products: \(BaSO_4+KNO_3\) (second option for products)