Question

1. claim: the average number of times people press the snooze button before getting out of bed is more than 5. so your hypotheses are: \\( h_0 : \mu = 5 \\) \\( h_a : \mu > 5 \\) you surveyed 36 people and found that the average number of snooze presses was 6.8 with a standard deviation of 2.5. fill in the following: (if you have to round, round to 2 decimal places.) stat= \\( \square \\) null= \\( \square \\) se= \\( \square \\) t.s. = \\( \square \\) assuming the null is true, would this be weird? type yes or no. \\( \square \\)

Explanation:

Step1: Identify stat value

stat = sample mean = 6.8

Step2: Identify null value

null = hypothesized mean = 5

Step3: Calculate SE

SE = $\frac{s}{\sqrt{n}} = \frac{2.5}{\sqrt{36}} = \frac{2.5}{6} \approx 0.42$

Step4: Calculate t-statistic

t = $\frac{\text{stat} - \text{null}}{SE} = \frac{6.8 - 5}{0.42} \approx 4.29$

Step5: Judge if weird

t=4.29 is far from 0, so weird.

Answer:

stat=6.8
null=5
SE=0.42
t.s=4.29
yes