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1. change the exponential expression to an equivalent expression involv…

Question

  1. change the exponential expression to an equivalent expression involving a logarithm.

$a^7 = 22$
the equivalent equation in logarithmic form is
(type an equation. use integers or fractions for any numbers in the equation.)

  1. suppose that $f(x) = 7^{-x}$

(a) what is $f(4)$? when $x = 4$, what is the point on the graph of $f$?
(b) if $f(x) = \frac{1}{49}$, what is $x$? when $f(x) = \frac{1}{49}$, what is the point on the graph of $f$?
(a) $f(4) = $ the point $\quad$ is on the graph of $f$
(do not use commas in any individual coordinates.)
(b) if $f(x) = \frac{1}{49}, x = $ the point $\quad$ is on the graph of $f$
(do not use commas in any individual coordinates.)

  1. simplify the expression

$\frac{(2a^9)^2}{(2a^9)^3}$
(simplify your answer.)

  1. find the value(s) of the variable for which the rational expression is undefined

$\frac{5p}{p - 2}$
select the correct choice below and, if necessary, fill in the answer box to complete your choice.
\\(\boldsymbol{\circ}\\) a. the expression is undefined for $p = $
(type an integer or a simplified fraction. use a comma to separate answers as needed.)
\\(\boldsymbol{\circ}\\) b. there are no values for which the expression is undefined.

  1. use the negative exponent rules to simplify. write the answer with positive exponents only.

$\left(\frac{6}{5}\
ight)^{-3}$
$\left(\frac{6}{5}\
ight)^{-3} = $ (type an integer or a simplified fraction.)

Explanation:

Question 1

Step1: Recall the exponential - logarithmic conversion rule

The exponential equation \(y = a^{x}\) is equivalent to the logarithmic equation \(\log_{a}y=x\). Given the exponential equation \(a^{x}=22\), we can apply this rule. Here, \(y = 22\), the base \(a\) remains the same, and the exponent \(x\) is the value of the logarithm.

Step2: Write the logarithmic form

Using the rule \(\log_{a}y = x\) for \(a^{x}=22\), we get \(\log_{a}22=x\)

Step1: Evaluate \(f(4)\) for \(f(x)=7^{x}\)

To find \(f(4)\), we substitute \(x = 4\) into the function \(f(x)=7^{x}\). So \(f(4)=7^{4}\)

Step2: Calculate \(7^{4}\)

\(7^{4}=7\times7\times7\times7 = 2401\)

Step3: Find the point on the graph

For a function \(y = f(x)\), when \(x = 4\), \(y=f(4)=2401\). So the point on the graph is \((4,2401)\)

Step1: Solve \(f(x)=\frac{1}{49}\) for \(x\) when \(f(x)=7^{x}\)

We know that \(\frac{1}{49}=\frac{1}{7^{2}}=7^{- 2}\). Since \(f(x)=7^{x}\) and \(f(x)=\frac{1}{49}=7^{-2}\), then \(7^{x}=7^{-2}\)

Step2: Use the property of exponential functions

If \(a^{m}=a^{n}\) (\(a>0,a
eq1\)), then \(m = n\). So for \(7^{x}=7^{-2}\), we have \(x=-2\)

Step3: Find the point on the graph

When \(x=-2\), \(y = f(-2)=\frac{1}{49}\). So the point on the graph is \((-2,\frac{1}{49})\)

Answer:

\(\log_{a}22 = x\)

Question 2 (a)