Question

a carboxylic acid can be reduced to form the alcohol ch₃ch(ch₃)ch₂oh, commonly known as isobutanol. complete the structure of the carboxylic acid that is reduced to isobutanol. fill in the missing atoms or groups.
provide your answer below:

Explanation:

Step1: Analyze the reduction reaction

Carboxylic acids \( (R - COOH) \) are reduced to alcohols \( (R - CH_2OH) \) by strong reducing agents like \( LiAlH_4 \). The general formula for the reduction is \( RCOOH+4[H]\xrightarrow{LiAlH_4}RCH_2OH + H_2O \).

Step2: Determine the structure of the carboxylic acid

The alcohol is \( CH_3CH(CH_3)CH_2OH \). The corresponding carboxylic acid should have a \( -COOH \) group. The carbon - chain of the carboxylic acid is the same as that of the alcohol. So, the carboxylic acid is \( CH_3CH(CH_3)COOH \).
In the given partial structure \( CH_3 - C - C \), the first \( C \) (attached to \( CH_3 \) and \( H \)) has a tetra - valent carbon. The second \( C \) (in the \( -COOH \) group) is part of a carbonyl \( (C = O) \) and a hydroxyl \( (-OH) \) group.
The structure of the carboxylic acid \( CH_3CH(CH_3)COOH \) can be written as \( CH_3-\underset{\underset{H}{\vert}}{C}-\underset{\underset{OH}{\vert}}{C}=O \). So the missing groups are \( -OH \) (on the second \( C \) for the \( -COOH \) group), \( =O \) (for the carbonyl part of the \( -COOH \) group), and \( -H \) (to complete the tetra - valency of the first \( C \) atom).

Answer:

The missing atoms or groups are \( -OH \), \( =O \), and \( -H \).