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calculate the volume in milliliters of a 0.852 mol/l sodium carbonate s…

Question

calculate the volume in milliliters of a 0.852 mol/l sodium carbonate solution that contains 75.0 mmol of sodium carbonate (na₂co₃). round your answer to 3 significant digits.

Explanation:

Step1: Convert millimoles to moles

Since \(1\space mol = 1000\space mmol\), then \(n = 75.0\space mmol=\frac{75.0}{1000}\space mol = 0.0750\space mol\)

Step2: Use the molarity formula \(M=\frac{n}{V}\) to find \(V\)

The molarity formula is \(M=\frac{n}{V}\), where \(M = 0.852\space mol/L\) and \(n=0.0750\space mol\). Rearranging for \(V\) gives \(V=\frac{n}{M}\)
Substitute the values: \(V=\frac{0.0750\space mol}{0.852\space mol/L}\approx0.0880\space L\)

Step3: Convert liters to milliliters

Since \(1\space L = 1000\space mL\), then \(V = 0.0880\space L\times1000\space mL/L=88.0\space mL\)

Answer:

\(88.0\space mL\)