Question

calculate the volume that a 0.323 - mol sample of a gas will occupy at 265 k and a pressure of 0.900 atm.

Explanation:

Step1: Recall the ideal gas law

The ideal gas law is \(PV = nRT\), where \(P\) is pressure (in atm), \(V\) is volume (in L), \(n\) is the number of moles, \(R\) is the ideal gas constant (\(R= 0.0821\space L\cdot atm/(mol\cdot K)\)), and \(T\) is temperature (in K). We need to solve for \(V\), so \(V=\frac{nRT}{P}\).

Step2: Substitute the given values

Given \(n = 0.323\space mol\), \(R = 0.0821\space L\cdot atm/(mol\cdot K)\), \(T=265\space K\), and \(P = 0.900\space atm\).

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Answer:

7.81 L