Question

calculate the molar concentration a solution containing 9.73e+2 grams of c₆h₁₂o₆ in 82 milliliters of water.

Explanation:

Step1: Calculate molar mass of \(C_6H_{12}O_6\)

Molar mass of \(C = 12\space g/mol\), \(H=1\space g/mol\), \(O = 16\space g/mol\)
\(M=(6\times12)+(12\times1)+(6\times16)=72 + 12+96=180\space g/mol\)

Step2: Calculate moles of \(C_6H_{12}O_6\)

Use formula \(n=\frac{m}{M}\), where \(m = 973\space g\) (since \(9.73e + 2=973\)), \(M = 180\space g/mol\)
\(n=\frac{973}{180}\approx5.406\space mol\)

Step3: Convert volume to liters

\(V = 82\space mL=0.082\space L\) (since \(1\space L = 1000\space mL\))

Step4: Calculate molar concentration

Use formula \(C=\frac{n}{V}\)
\(C=\frac{5.406}{0.082}\approx65.93\space mol/L\)

Answer:

\(65.93\)