Question

a bowl has 8 green grapes and 15 red grapes. henry randomly chooses a grape, eats it, and then chooses another grape. what is the probability that both grapes are green? about 12.6% about 12.1% about 11.1% about 10.6%

Explanation:

Step1: Calculate total grapes initially

Total grapes = 8 green + 15 red = 23
Probability first grape is green: $\frac{8}{23}$

Step2: Calculate remaining grapes after first green

Remaining grapes = 23 - 1 = 22; remaining green = 8 - 1 = 7
Probability second grape is green: $\frac{7}{22}$

Step3: Multiply probabilities for both green

Combined probability = $\frac{8}{23} \times \frac{7}{22} = \frac{56}{506} \approx 0.1107$ (11.1%)

Answer:

about 11.1%