Question

based on mendels pea plant punnett square crosses, what will be the probability that a pea plant will be yellow if two homozygous green pea plants are crossed? parent 1 yy parent 2 yy 50% 25% 100% 0%

Explanation:

Step1: Analyze Parent Genotypes

Both parents are homozygous green with genotype \( yy \). This means each parent can only contribute a \( y \) allele to the offspring.

Step2: Determine Offspring Genotypes

When we cross \( yy \) (Parent 1) with \( yy \) (Parent 2), all offspring will inherit one \( y \) from each parent, so all offspring will have the genotype \( yy \).

Step3: Relate Genotype to Phenotype

The genotype \( yy \) results in the green phenotype (since yellow is typically associated with a dominant allele, and here we have only the recessive \( y \) alleles). So, there are no offspring with the yellow phenotype.

Step4: Calculate Probability

The probability of an event (yellow pea plant) is the number of favorable outcomes (yellow plants) divided by the total number of outcomes (all plants). Since there are 0 favorable outcomes, the probability is \( 0\% \).

Answer:

0%