Question

balancing equations
type coefficients to balance the equation.
you can also
copy & paste these!
build a graphical version of the balanced equation.
(view the example on slide #17)

Explanation:

Step1: Balance nitrogen atoms

On the left - hand side, there is 1 nitrogen atom in \(Ag_3N\). On the right - hand side, there are 2 nitrogen atoms in \(N_2\). To balance the nitrogen atoms, we put a coefficient of 2 in front of \(Ag_3N\). So the equation becomes \(2Ag_3N
ightarrow Ag + N_2\). Now, the number of nitrogen atoms on both sides is 2.

Step2: Balance silver atoms

After putting a coefficient of 2 in front of \(Ag_3N\), the number of silver atoms on the left - hand side is \(2\times3 = 6\). To balance the silver atoms, we put a coefficient of 6 in front of \(Ag\) on the right - hand side. The balanced equation is \(2Ag_3N
ightarrow6Ag + N_2\).

Answer:

The coefficients are 2, 6, 1. So the blanks (from left to right) are filled with 2, 6, 1.