Question

balance the equation
albr₃ + k₂so₄ → kbr + al₂(so₄)₃

Explanation:

Step1: Balance aluminum atoms

On the right - hand side, there are \(2\) \(Al\) atoms in \(Al_2(SO_4)_3\). So, put a coefficient of \(2\) in front of \(AlBr_3\) on the left - hand side.
\(2AlBr_3+K_2SO_4
ightarrow KBr + Al_2(SO_4)_3\)

Step2: Balance bromine atoms

Since there are \(6\) \(Br\) atoms in \(2AlBr_3\), put a coefficient of \(6\) in front of \(KBr\) on the right - hand side.
\(2AlBr_3+K_2SO_4
ightarrow6KBr + Al_2(SO_4)_3\)

Step3: Balance potassium and sulfate atoms

There are \(6\) \(K\) atoms in \(6KBr\). So, put a coefficient of \(3\) in front of \(K_2SO_4\) on the left - hand side. Now, for sulfate \((SO_4)\) groups, there are \(3\) \(SO_4\) groups in \(3K_2SO_4\) and \(3\) \(SO_4\) groups in \(Al_2(SO_4)_3\).
\(2AlBr_3 + 3K_2SO_4
ightarrow6KBr+Al_2(SO_4)_3\)

Answer:

\(2\) \(AlBr_3\), \(3\) \(K_2SO_4\), \(6\) \(KBr\), \(1\) \(Al_2(SO_4)_3\)