assignment
solve each equation.
1) $-31 = x + -13$

3) $-5 = k + 1$

5) $-12 = -4 - k$

7) $2 + n = -10 - 2n$

9) $-5b - 1 + 8 = -8b - 11$

Question

assignment
solve each equation.
1) $-31 = x + -13$

3) $-5 = k + 1$

5) $-12 = -4 - k$

7) $2 + n = -10 - 2n$

9) $-5b - 1 + 8 = -8b - 11$

Accepted Answer

### 1) Solve $-31 = x + (-13)$
# Explanation:
## Step1: Simplify the equation
The equation is $-31=x - 13$ (since $x+(- 13)=x - 13$).
## Step2: Isolate $x$
Add $13$ to both sides of the equation.
$-31 + 13=x-13 + 13$
$-18=x$

# Answer: $x=-18$

### 3) Solve $-5=k + 1$
# Explanation:
## Step1: Isolate $k$
Subtract $1$ from both sides of the equation.
$-5-1=k + 1-1$
## Step2: Simplify
$-6 = k$

# Answer: $k=-6$

### 5) Solve $-12=-4 - k$
# Explanation:
## Step1: Isolate the term with $k$
Add $k$ to both sides: $-12 + k=-4-k + k$, which simplifies to $-12 + k=-4$
## Step2: Isolate $k$
Add $12$ to both sides: $-12 + k+12=-4 + 12$
$k = 8$

# Answer: $k = 8$

### 7) Solve $2 + n=-10-2n$
# Explanation:
## Step1: Collect like terms
Add $2n$ to both sides: $2 + n+2n=-10-2n+2n$, which gives $2 + 3n=-10$
## Step2: Isolate the term with $n$
Subtract $2$ from both sides: $2+3n - 2=-10 - 2$
$3n=-12$
## Step3: Solve for $n$
Divide both sides by $3$: $\frac{3n}{3}=\frac{-12}{3}$
$n=-4$

# Answer: $n=-4$

### 9) Solve $-5b-1 + 8=-8b-11$
# Explanation:
## Step1: Simplify the left side
Combine like terms: $-5b+7=-8b-11$
## Step2: Collect like terms
Add $8b$ to both sides: $-5b + 8b+7=-8b+8b-11$
$3b+7=-11$
## Step3: Isolate the term with $b$
Subtract $7$ from both sides: $3b+7 - 7=-11 - 7$
$3b=-18$
## Step4: Solve for $b$
Divide both sides by $3$: $\frac{3b}{3}=\frac{-18}{3}$
$b=-6$

# Answer: $b=-6$

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QUESTION IMAGE

Question

Explanation:

1) Solve \(-31 = x + (-13)\)

Step1: Simplify the equation

Step2: Isolate \(x\)

Step1: Isolate \(k\)

Step2: Simplify

Step1: Isolate the term with \(k\)

Step2: Isolate \(k\)

Answer:

3) Solve \(-5=k + 1\)