Question

answer the questions about the reaction that you just balanced. 2 c₆h₁₀ + 17 o₂ → 12 co₂ + 10 h₂o the reaction starts with o₂ and so is a 1 reaction. o₂ is an element and is converted into a compound. another way to analyze a reaction is to assign oxidation numbers. the c in c₆h₁₀ is c⁻⁴ and is oxidized to c⁺⁴ in co₂. the o in o₂ is o⁰ and is 2 to o⁻² in both co₂ and h₂o. is this a redox reaction? (yes/no)3. burning or combustion reactions are known to be exothermic. also, the products are known to be stable. will the reaction happen as it is written? (yes/no)4. the reverse reaction would not happen. how oxidation numbers are assigned: in c₆h₁₀ the most electronegative element is c. thus, c gets a (-) number and h gets a (+) number in o₂ each o gets a 0 because o₂ is an element in co₂ the most electronegative element is o. thus, o gets a (-) number and c gets a (+) number in h₂o the most electronegative element is o. thus o gets a (-) and h gets a (+) number the possible oxidation numbers are given on the

Explanation:

1. Combustion reactions involve a substance reacting with oxygen. Here, \(C_6H_{10}\) reacts with \(O_2\), so it is a combustion reaction.
2. Reduction is the gain of electrons or a decrease in oxidation state. The oxidation state of \(O\) changes from \(0\) in \(O_2\) to \(- 2\) in \(CO_2\) and \(H_2O\), so \(O\) is reduced.
3. A redox reaction has both oxidation (increase in oxidation state, \(C\) from \(-4\) to \(+4\)) and reduction (decrease in oxidation state, \(O\) from \(0\) to \(-2\)). So it is a redox reaction.
4. Combustion reactions are spontaneous in the forward direction (as written) because they are exothermic and form stable products (\(CO_2\) and \(H_2O\)).

Answer:

1. combustion
2. reduced
3. yes
4. yes