Question

ammonium phosphate ((nh4)3 po4) is an important ingredient in many solid fertilizers. it can be made by reacting aqueous phosphoric acid (h3po4) with liquid ammonia. calculate the moles of ammonium phosphate produced by the reaction of 1.9 mol of phosphoric acid. be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Explanation:

Step1: Write the balanced chemical equation

$$\ce{H3PO4 + 3NH3->(NH4)3PO4}$$
From the equation, the mole ratio of $\ce{H3PO4}$ to $\ce{(NH4)3PO4}$ is $1:1$.

Step2: Calculate the moles of ammonium phosphate

Since the mole ratio of $\ce{H3PO4}$ to $\ce{(NH4)3PO4}$ is $1:1$, the moles of $\ce{(NH4)3PO4}$ produced is equal to the moles of $\ce{H3PO4}$ reacted.
Given $n(\ce{H3PO4}) = 1.9\space mol$, so $n(\ce{(NH4)3PO4})=1.9\space mol$

Answer:

$1.9\space mol$