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6r ≤ -24 \frac{d}{4} ≤ -3

Question

6r ≤ -24

\frac{d}{4} ≤ -3

Explanation:

For the inequality \( 6r \leq -24 \)

Step 1: Isolate \( r \)

To solve for \( r \), divide both sides of the inequality \( 6r \leq -24 \) by 6. Since 6 is a positive number, the direction of the inequality sign remains the same.

$$ \frac{6r}{6} \leq \frac{-24}{6} $$

Step 2: Simplify

Simplifying both sides gives:

$$ r \leq -4 $$
For the inequality \( \frac{d}{4} \leq -3 \)

Step 1: Isolate \( d \)

To solve for \( d \), multiply both sides of the inequality \( \frac{d}{4} \leq -3 \) by 4. Since 4 is a positive number, the direction of the inequality sign remains the same.

$$ 4\times\frac{d}{4} \leq 4\times(-3) $$

Step 2: Simplify

Simplifying both sides gives:

$$ d \leq -12 $$

Answer:

For \( 6r \leq -24 \), the solution is \( r \leq -4 \).
For \( \frac{d}{4} \leq -3 \), the solution is \( d \leq -12 \).