QUESTION IMAGE
Question
6b + 15 = 120 + 3b
b = \boxed{}
Step1: Subtract 3b from both sides
To isolate the variable terms on one side, we subtract \(3b\) from both sides of the equation \(6b + 15 = 120 + 3b\). This gives us \(6b - 3b + 15 = 120 + 3b - 3b\), which simplifies to \(3b + 15 = 120\).
Step2: Subtract 15 from both sides
Next, we subtract 15 from both sides to isolate the term with the variable. So, \(3b + 15 - 15 = 120 - 15\), which simplifies to \(3b = 105\).
Step3: Divide both sides by 3
To solve for \(b\), we divide both sides of the equation \(3b = 105\) by 3. This gives us \(\frac{3b}{3}=\frac{105}{3}\), so \(b = 35\).
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35