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6b + 15 = 120 + 3b b = \\boxed{}

Question

6b + 15 = 120 + 3b
b = \boxed{}

Explanation:

Step1: Subtract 3b from both sides

To isolate the variable terms on one side, we subtract \(3b\) from both sides of the equation \(6b + 15 = 120 + 3b\). This gives us \(6b - 3b + 15 = 120 + 3b - 3b\), which simplifies to \(3b + 15 = 120\).

Step2: Subtract 15 from both sides

Next, we subtract 15 from both sides to isolate the term with the variable. So, \(3b + 15 - 15 = 120 - 15\), which simplifies to \(3b = 105\).

Step3: Divide both sides by 3

To solve for \(b\), we divide both sides of the equation \(3b = 105\) by 3. This gives us \(\frac{3b}{3}=\frac{105}{3}\), so \(b = 35\).

Answer:

35