Question

\

$$\begin{cases} y = 5 - x \\\\ 1 = 4x + 3y \\end{cases}$$

Explanation:

Step1: Substitute \( y = 5 - x \) into the second equation

We have the system of equations \(

$$\begin{cases}y = 5 - x\\1 = 4x + 3y\end{cases}$$

\). Substitute \( y = 5 - x \) into \( 1 = 4x + 3y \), we get \( 1 = 4x + 3(5 - x) \).

Step2: Simplify and solve for \( x \)

Simplify the equation \( 1 = 4x + 15 - 3x \), which becomes \( 1 = x + 15 \). Subtract 15 from both sides, we have \( x = 1 - 15=- 14 \).

Step3: Substitute \( x = - 14 \) into \( y = 5 - x \) to find \( y \)

Substitute \( x=-14\) into \( y = 5 - x \), we get \( y = 5-(-14)=5 + 14 = 19 \).

Answer:

The solution of the system of equations is \( x=-14,y = 19 \)