Question

4x - 2y if x = -2 and y = 0.
1.) 4x + -2y = 4(-2) + -2(0 )
= -
2.) 7r - 8s if r = -3 and s = -3

3.) c - 3d if c = -3 and d = -4.
4.) 3x - 5y if x = -3 and y = 2

5.) -3x + 4 - 2y if x = 3 and y = -2.
6.) 4x - 3 + 2y if x = -2 and y = -3.

Explanation:

Step1: Solve \(4x - 2y\) when \(x = -2\), \(y = 0\)

Substitute \(x = -2\) and \(y = 0\) into \(4x - 2y\):
\(4(-2) - 2(0) = -8 - 0 = -8\)

Step2: Solve \(7r - 8s\) when \(r = -3\), \(s = -3\)

Substitute \(r = -3\) and \(s = -3\) into \(7r - 8s\):
\(7(-3) - 8(-3) = -21 + 24 = 3\)

Step3: Solve \(c - 3d\) when \(c = -3\), \(d = -4\)

Substitute \(c = -3\) and \(d = -4\) into \(c - 3d\):
\(-3 - 3(-4) = -3 + 12 = 9\)

Step4: Solve \(3x - 5y\) when \(x = -3\), \(y = 2\)

Substitute \(x = -3\) and \(y = 2\) into \(3x - 5y\):
\(3(-3) - 5(2) = -9 - 10 = -19\)

Step5: Solve \(-3x + 4 - 2y\) when \(x = 3\), \(y = -2\)

Substitute \(x = 3\) and \(y = -2\) into \(-3x + 4 - 2y\):
\(-3(3) + 4 - 2(-2) = -9 + 4 + 4 = -1\)

Step6: Solve \(4x - 3 + 2y\) when \(x = -2\), \(y = -3\)

Substitute \(x = -2\) and \(y = -3\) into \(4x - 3 + 2y\):
\(4(-2) - 3 + 2(-3) = -8 - 3 - 6 = -17\)

Answer:

1. \(\boldsymbol{-8}\)
2. \(\boldsymbol{3}\)
3. \(\boldsymbol{9}\)
4. \(\boldsymbol{-19}\)
5. \(\boldsymbol{-1}\)
6. \(\boldsymbol{-17}\)