Question

if 30.0 l of oxygen gas is cooled from 473 k to 274 k at constant pressure, what is the new volume of oxygen? 17.4 l 23.0 l 0.150 l 51.8 l 60.0 l

Explanation:

Step1: Identify the formula

Charles's Law: $\frac{V_1}{T_1}=\frac{V_2}{T_2}$ (where $V_1 = 30.0\ L$, $T_1 = 473\ K$, $T_2=274\ K$, and $V_2$ is the unknown volume).

Step2: Rearrange the formula to solve for $V_2$

$V_2=\frac{V_1\times T_2}{T_1}$

Step3: Substitute the values

$V_2=\frac{30.0\ L\times274\ K}{473\ K}$

Step4: Calculate

$V_2=\frac{8220}{473}\ L\approx17.4\ L$

Answer:

17.4 L