Question

1. geometry write and solve an inequality to find the values of x for which the area of the rectangle is greater than the area of the triangle. rectangle with length 12 and width x+2; triangle with base x+16 and height 10 (dashed line with right angle) 3-5 solving inequalities with variables on both sides 197

Explanation:

Step1: Calculate rectangle area

Area_rectangle = 12*(x + 2)

Step2: Calculate triangle area

Area_triangle = ( (x + 16)10 )/2 = 5(x + 16)

Step3: Set up inequality

12(x + 2) > 5(x + 16)

Step4: Expand both sides

12x + 24 > 5x + 80

Step5: Solve for x

7x > 56 ⇒ x > 8

Answer:

x > 8