Question

1. you now have the correct number of co₂ and h₂o molecules on the reactant side. you also have one glucose on the product side. however, the byproduct of photosynthesis is o₂. the current state of the equation does not have the same number of oxygen atoms on both reactant and product sides. you need to adjust the number of o₂ molecules formed during photosynthesis. calculate the number of o₂ molecules that must be formed during photosynthesis for every glucose that is created.

Explanation:

Step1: Write the un - balanced equation

The general form of the photosynthesis equation is \(CO_{2}+H_{2}O
ightarrow C_{6}H_{12}O_{6}+O_{2}\). Let's assume the number of \(CO_{2}\) molecules is \(x\) and \(H_{2}O\) molecules is \(y\). For carbon balance: since there are 6 carbon atoms in \(C_{6}H_{12}O_{6}\), from \(CO_{2}\), we have \(x = 6\) (because each \(CO_{2}\) has 1 carbon atom). For hydrogen balance: since there are 12 hydrogen atoms in \(C_{6}H_{12}O_{6}\) and each \(H_{2}O\) has 2 hydrogen atoms, from \(H_{2}O\), \(y=\frac{12}{2}=6\).
The equation becomes \(6CO_{2}+6H_{2}O
ightarrow C_{6}H_{12}O_{6}+O_{2}\).

Step2: Calculate the number of oxygen atoms on the reactant side

On the reactant side, the number of oxygen atoms: In \(6CO_{2}\), the number of oxygen atoms is \(6\times2 = 12\); in \(6H_{2}O\), the number of oxygen atoms is \(6\times1=6\). So the total number of oxygen atoms on the reactant side is \(12 + 6=18\).

Step3: Calculate the number of oxygen atoms on the product side from glucose

In \(C_{6}H_{12}O_{6}\), the number of oxygen atoms is 6. Let the number of \(O_{2}\) molecules be \(z\). The number of oxygen atoms from \(O_{2}\) is \(2z\).

Step4: Set up an equation for oxygen balance

Since the number of oxygen atoms on the reactant and product sides must be equal, we have \(18=6 + 2z\).
Solve for \(z\):

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Answer:

6