Question

1. how many oxygen atoms are present on the reactant side before balancing the equation ( ch_{4}+o_{2}

ightarrow co_{2}+h_{2}o )?
a. 3
b. 4
c. 5
d. 2

Explanation:

Step1: Identify reactants

Reactants are \(CH_4\) and \(O_2\).

Step2: Count oxygen atoms in reactants

In \(CH_4\), there are \(0\) oxygen atoms. In \(O_2\), there are \(2\) oxygen atoms (since the sub - script of \(O\) in \(O_2\) is \(2\)).

Answer:

D. 2