Question

19/20 if the area of a square is 36, what is the value of x? 3x 10 8 6 2

Explanation:

Step1: Recall area formula for square

The area \( A \) of a square is given by \( A = s^2 \), where \( s \) is the side length. Here, the side length is \( 3x \), and the area is 36. So we set up the equation \( (3x)^2 = 36 \).

Step2: Simplify the equation

First, expand \( (3x)^2 \) to get \( 9x^2 = 36 \). Then, divide both sides by 9: \( x^2 = \frac{36}{9} = 4 \).

Step3: Solve for x

Take the square root of both sides. \( x = \pm\sqrt{4} \), but since we're dealing with a length - related variable (implied by the square's side), we consider the positive root. Wait, but let's check the options. Wait, maybe I made a mistake. Wait, no, wait the side length is \( 3x \), and the area is 36, so \( (3x)^2=36 \) → \( 9x^2 = 36 \) → \( x^2 = 4 \) → \( x = 2 \) (since length can't be negative, and 2 is one of the options). Wait, let's verify: if \( x = 2 \), then the side length is \( 3\times2=6 \), and the area is \( 6^2 = 36 \), which matches.

Answer:

2 (the option with value 2)