Question

18
a factorys electricity bill is based on a fixed monthly
service charge of $75, plus $0.08 per kilowatt - hour
(kwh) of electricity used. if the factory has a budget of
$600 for electricity this month, what is the maximum
number of kilowatt - hours they can use while staying
within budget?

Explanation:

Step1: Set up the inequality

Let \(n\) be the number of kilowatt - hours. The total cost \(C\) is given by \(C = 75+0.08n\). Since the budget is \(600\), we have the inequality \(75 + 0.08n\leqslant600\).

Step2: Solve for \(n\)

Subtract \(75\) from both sides: \(0.08n\leqslant600 - 75\). So \(0.08n\leqslant525\).
Then divide both sides by \(0.08\): \(n\leqslant\frac{525}{0.08}\).
Calculate \(\frac{525}{0.08}=6562.5\).

Answer:

\(6562.5\)