Question

1. the presence of freckles (f) is dominant to no freckles (f). jake and his mom have freckles, but his sister and dad do not have freckles. complete the punnett square that shows jakes family. dad mom phenotype probability (%) freckles: no freckles:

Explanation:

Step1: Determine parents' genotypes

Since no freckles (f) is recessive and Dad has no freckles, Dad's genotype is ff. Jake's sister has no freckles (ff), so she must get one f from each parent. Mom has freckles but gives an f to her daughter, so Mom's genotype is Ff.

Step2: Create Punnett square

Mom (Ff) can produce gametes F and f. Dad (ff) can only produce f.

	f	f
f	ff	ff

Step3: Calculate probabilities

There are 4 offspring possibilities. 2 are Ff (freckles) and 2 are ff (no freckles).
Freckles probability: $\frac{2}{4}= 50\%$
No - freckles probability: $\frac{2}{4}=50\%$

Answer:

Freckles: 50%
No Freckles: 50%