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12 \\frac{w^{13}x^{5}y^{14}z^{3}}{7w^{8}y^{6}z^{14}}

Question

12
\frac{w^{13}x^{5}y^{14}z^{3}}{7w^{8}y^{6}z^{14}}

Explanation:

Step1: Simplify coefficients and variables separately

For the coefficient, we have \( \frac{1}{7} \) (since there's no coefficient in the numerator except 1 implied, and 7 in the denominator). For the variable \( w \): use the rule \( \frac{a^m}{a^n}=a^{m - n} \), so \( w^{13-8}=w^5 \). For \( x \): \( x^{5-0}=x^5 \) (since \( x^0 = 1\) in the denominator, so exponent of \( x \) in denominator is 0). For \( y \): \( y^{14 - 6}=y^8 \). For \( z \): \( z^{3-14}=z^{- 11}=\frac{1}{z^{11}} \).

Step2: Combine all simplified parts

Multiply the coefficient and the simplified variables: \( \frac{1}{7}\times w^5\times x^5\times y^8\times\frac{1}{z^{11}}=\frac{w^5x^5y^8}{7z^{11}} \)

Answer:

\( \boldsymbol{\frac{w^5x^5y^8}{7z^{11}}} \)