QUESTION IMAGE
Question
- $8x^3 + 27$
find each product by using square of sums.
- $(x + 3)^2$
- $(6x + 3y)^2$
find each product by using square of differences.
- $(x - 2)^2$
- $(2a - 3b)^2$
Problem 11: \(8x^3 + 27\)
Step1: Identify the formula
This is a sum of cubes. The formula for sum of cubes is \(a^3 + b^3=(a + b)(a^2 - ab + b^2)\). Here, \(8x^3=(2x)^3\) and \(27 = 3^3\), so \(a = 2x\) and \(b = 3\).
Step2: Apply the formula
Substitute \(a = 2x\) and \(b = 3\) into the formula:
Step1: Recall the formula
The square of a sum formula is \((a + b)^2=a^2+2ab + b^2\). Here, \(a=x\) and \(b = 3\).
Step2: Apply the formula
Substitute \(a=x\) and \(b = 3\) into the formula:
Step1: Recall the formula
The square of a sum formula is \((a + b)^2=a^2+2ab + b^2\). Here, \(a = 6x\) and \(b=3y\).
Step2: Apply the formula
Substitute \(a = 6x\) and \(b = 3y\) into the formula:
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\((2x + 3)(4x^2-6x + 9)\)