Question

10 a machine puts out 6000 joules of work. to produce that much work from the machine requires the user to put in 8000 joules of work. find the percent efficiency of the machine. (efficiency = \\( \frac { output work } { input work } \times 100 \\) ) a 133% b 100% c 75% d 25%

Explanation:

Step1: Substitute values into formula

Given \( Output\ Work = 6000\) joules and \( Input\ Work = 8000\) joules. Substitute into \( Efficiency=\frac{Output\ Work}{Input\ Work}\times100\). So \( Efficiency=\frac{6000}{8000}\times100\).

Step2: Simplify the fraction

Simplify \(\frac{6000}{8000}=\frac{6}{8}=\frac{3}{4}\). Then \( Efficiency=\frac{3}{4}\times100\).

Step3: Calculate the percentage

\(\frac{3}{4}\times100 = 75\).

Answer:

C. \(75\%\)