6. 1 ______ = 10⁻¹ m 12 1 ______ = 10⁻¹⁵ m 13. 1250.01 g = ______ kg 14. 10798 mg = ______ kg 15. 2.5 km = ______ m 16. 474 cm = ______ m 17. 2317 na = ______ a 18. 1038 ha = ______ a 19. why is the metric system better to use in science class than the english system (with feet, yards, and miles)? 20. if someone offered you 5 milliliters, 5 deciliters, or 5 decaliters of ice cream to eat right now, which would you pick? explain your answer! (c) bethany lau

Question

Accepted Answer

### Question 13:
# Explanation:
## Step1: Recall unit conversion (g to kg)
We know that $ 1\space kg = 1000\space g $, so to convert grams to kilograms, we divide by 1000 (or multiply by $ 10^{-3} $).
## Step2: Perform the conversion
For $ 1250.01\space g $, the conversion is $ 1250.01\space g\times\frac{1\space kg}{1000\space g} = 1250.01\times10^{-3}\space kg $
Calculating $ 1250.01\times10^{-3} = 1.25001 $
# Answer:
$ 1.25001 $

### Question 14:
# Explanation:
## Step1: Recall unit conversions (mg to g to kg)
First, $ 1\space g = 1000\space mg $ and $ 1\space kg = 1000\space g $. So, to convert mg to kg, we divide by $ 1000\times1000 = 10^6 $ (or multiply by $ 10^{-6} $).
## Step2: Perform the conversion
For $ 10798\space mg $, the conversion is $ 10798\space mg\times\frac{1\space kg}{10^6\space mg} = 10798\times10^{-6}\space kg $
Calculating $ 10798\times10^{-6}= 0.010798 $
# Answer:
$ 0.010798 $

### Question 15:
# Explanation:
## Step1: Recall unit conversion (km to m)
We know that $ 1\space km = 1000\space m $, so to convert kilometers to meters, we multiply by 1000 (or $ 10^3 $).
## Step2: Perform the conversion
For $ 2.5\space km $, the conversion is $ 2.5\space km\times\frac{1000\space m}{1\space km}=2.5\times 1000\space m $
Calculating $ 2.5\times1000 = 2500 $
# Answer:
$ 2500 $

### Question 16:
# Explanation:
## Step1: Recall unit conversion (cm to m)
We know that $ 1\space m = 100\space cm $, so to convert centimeters to meters, we divide by 100 (or multiply by $ 10^{-2} $).
## Step2: Perform the conversion
For $ 474\space cm $, the conversion is $ 474\space cm\times\frac{1\space m}{100\space cm}=474\times10^{-2}\space m $
Calculating $ 474\times10^{-2}= 4.74 $
# Answer:
$ 4.74 $

### Question 17:
# Explanation:
## Step1: Recall unit conversion (nA to A)
We know that $ 1\space nA = 10^{-9}\space A $, so to convert nanoamps to amps, we multiply by $ 10^{-9} $.
## Step2: Perform the conversion
For $ 2317\space nA $, the conversion is $ 2317\space nA\times\frac{1\space A}{10^9\space nA}=2317\times 10^{-9}\space A $
Calculating $ 2317\times10^{-9}= 2.317\times 10^{-6} $ (or $ 2.317\space \mu A $, but the question asks for A, so $ 2.317\times 10^{-6} $)
# Answer:
$ 2.317\times 10^{-6} $

### Question 18:
# Explanation:
## Step1: Recall unit conversion (hA to A)
We know that $ 1\space hA = 10\space A $ (hectoampere to ampere, since hecto is $ 10^2 $? Wait, no: hecto is $ 10^2 $? Wait, no, hecto is $ 10^2 $? Wait, no, kilo is $ 10^3 $, hecto is $ 10^2 $, deca is $ 10^1 $, deci is $ 10^{-1} $, centi $ 10^{-2} $, milli $ 10^{-3} $, micro $ 10^{-6} $, nano $ 10^{-9} $. Wait, no: $ 1\space hA = 100\space A $? Wait, no, hecto is $ 10^2 $, so $ 1\space hA = 10^2\space A = 100\space A $. Wait, the problem says "1038 hA = ____ A". So if $ 1\space hA = 100\space A $, then:
## Step2: Perform the conversion
$ 1038\space hA\times\frac{100\space A}{1\space hA}=1038\times 100\space A = 103800\space A $
Wait, but maybe there's a typo, maybe "hA" is "hA" (hectoampere) or maybe "mA"? But assuming hA is hectoampere ( $ 1\space hA = 100\space A $ ), then:
# Answer:
$ 103800 $ (assuming $ 1\space hA = 100\space A $)

### Question 19:
# Brief Explanations:
The metric system is better for science because it uses a **decimal (base - 10) system** for unit conversions. For example, converting between meters, centimeters, and kilometers involves moving the decimal point (e.g., $ 1\space km = 1000\space m = 100000\space cm $), which is simple. In the English system, conversions are irregular (e.g., $ 1\space yard = 3\space feet $, $ 1\space mile = 5280\space feet $), making calculations and comparisons more complex. The metric system also has a **universal standard** (used worldwide in science), ensuring consistency across experiments and regions.
# Answer:
The metric system uses a base - 10 (decimal) system for unit conversions (e.g., $ 1\space km = 10^3\space m $, $ 1\space m = 10^2\space cm $), which is simple. The English system has irregular conversions (e.g., $ 1\space mile = 5280\space feet $, $ 1\space yard = 3\space feet $), making calculations hard. The metric system is also universal in science, ensuring consistency.

### Question 20:
# Brief Explanations:
First, recall the metric prefixes:
- $ 1\space milliliter (mL)=10^{-3}\space L $, so $ 5\space mL = 5\times 10^{-3}\space L = 0.005\space L $
- $ 1\space deciliter (dL)=10^{-1}\space L $, so $ 5\space dL = 5\times 10^{-1}\space L = 0.5\space L $
- $ 1\space decaliter (daL)=10^{1}\space L $, so $ 5\space daL = 5\times 10^{1}\space L = 50\space L $

Ice cream is a food item, and a reasonable serving size is small. $ 5\space mL $ is very small (like a few drops), $ 5\space dL = 0.5\space L $ (about a half - liter, a more reasonable serving), and $ 5\space daL = 50\space L $ is extremely large (impractical to eat at once). So, if choosing to eat right now, $ 5\space dL $ is a reasonable amount (not too small, not too large).
# Answer:
I would pick 5 deciliters. Because $ 5\space mL = 0.005\space L $ (too small, like a few drops), $ 5\space dL = 0.5\space L $ (a reasonable serving), and $ 5\space daL = 50\space L $ (extremely large, impossible to eat at once). So 5 deciliters is a practical amount for immediate consumption.

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QUESTION IMAGE

Question

Explanation:

Question 13:

Step1: Recall unit conversion (g to kg)

Step2: Perform the conversion

Step1: Recall unit conversions (mg to g to kg)

Step2: Perform the conversion

Step1: Recall unit conversion (km to m)

Step2: Perform the conversion

Answer:

Question 14: