Question

if you push an object with twice the force while its mass stays the same, what happens to its acceleration? * 1 point it is cut in half it stays the same it doubles it quadruples

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration. We can solve for \(a\) to get \(a=\frac{F}{m}\).

Step2: Analyze the case when force is doubled

Let the initial force be \(F_1\) and the initial acceleration be \(a_1=\frac{F_1}{m}\). When the force is doubled (\(F_2 = 2F_1\)) and mass \(m\) remains the same, the new acceleration \(a_2=\frac{F_2}{m}=\frac{2F_1}{m}\).
Since \(a_1=\frac{F_1}{m}\), then \(a_2 = 2a_1\).

Answer:

It doubles.