Question

if you got:
$sqrt7{x^6}$ or $(sqrt7{x})^6$
gg
now find:
factor by grouping:
$x^3 + 3x^2 + 2x + 6$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(x^3 + 3x^2) + (2x + 6)$

Step2: Factor out GCF from each group

Factor out $x^2$ from the first group and $2$ from the second group: $x^2(x + 3) + 2(x + 3)$

Step3: Factor out the common binomial

Factor out $(x + 3)$ from both terms: $(x + 3)(x^2 + 2)$

Answer:

$(x + 3)(x^2 + 2)$