Question

if you had 3 ce amplifiers with the following gains $a_{v1} = 10$, $a_{v2} = 8$, $a_{v3} = 5$ and $v_s = 250$ mvrms. solve for the total gain $a_v$ round to the nearest two decimal places.
answer:

Explanation:

Step1: Recall total gain formula

For cascaded amplifiers, total voltage gain \( A_{V} \) is the product of individual gains. So \( A_{V}=A_{V1}\times A_{V2}\times A_{V3} \).

Step2: Substitute values

Substitute \( A_{V1} = 10 \), \( A_{V2}=8 \), \( A_{V3}=5 \) into the formula: \( A_{V}=10\times8\times5 \).

Step3: Calculate the product

\( 10\times8 = 80 \), then \( 80\times5 = 400 \). Since we need to round to two decimal places, it's \( 400.00 \).

Answer:

400.00