Question

1. you attempt to throw a pie at mrs. kelly as part of a fundraiser. you release the pie with a horizontal velocity of 1.3m/s. if it take 1s to hit the ground, a. how high did you throw it from? b. how far away from you does it land?

Explanation:

Step1: Analyze vertical motion for height

The vertical - motion of the pie is a free - fall motion. The initial vertical velocity $v_{0y}=0\ m/s$, the acceleration due to gravity $g = 9.8\ m/s^{2}$, and the time of flight $t = 1\ s$. We use the equation $y=v_{0y}t+\frac{1}{2}gt^{2}$.
Since $v_{0y}=0\ m/s$, the equation simplifies to $y=\frac{1}{2}gt^{2}$.
Substitute $g = 9.8\ m/s^{2}$ and $t = 1\ s$ into the equation: $y=\frac{1}{2}\times9.8\times1^{2}=4.9\ m$.

Step2: Analyze horizontal motion for horizontal distance

The horizontal motion of the pie is a uniform - motion because there is no horizontal acceleration ($a_x = 0$). The horizontal velocity $v_x=1.3\ m/s$ and the time of flight $t = 1\ s$. We use the equation $x = v_x t$.
Substitute $v_x=1.3\ m/s$ and $t = 1\ s$ into the equation: $x=1.3\times1 = 1.3\ m$.

Answer:

a. $4.9\ m$
b. $1.3\ m$