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Question
which of the following shows the equation \\(\log_4(x+6) = 2\\) rewritten using logarithms?
- \\(4^{\log_4(x+6)} = 2^2\\)
- \\(4^{\log_4(x+6)} = 4^4\\)
- \\(\log_4(x+6) = \log_4 16\\)
- \\(\log_4(x+6) = \log_2 16\\)
Rewrite the constant using a logarithm of base 4
$$
2 = \log_4(4^2) = \log_4(16)
$$
Substitute the rewritten constant back into the equation
$$
\log_4(x + 6) = \log_4(16)
$$
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- (A) \(4^{\log_4(x+6)} = 2^2\)
- (B) \(4^{\log_4(x+6)} = 4^4\)
- (C) \(\log_4(x+6) = \log_4 16\) (Correct answer)
- (D) \(\log_4(x+6) = \log_2 16\)