QUESTION IMAGE
Question
which of the following is the graph of this absolute value function?
\\y = -\frac{1}{2}|x|\\
Identify the vertex of the function
The given absolute value function is:
The general form of an absolute value function is \(y = a|x - h| + k\), where \((h, k)\) is the vertex. Here, \(h = 0\) and \(k = 0\), so the vertex is at the origin:
Determine the direction of opening
The coefficient \(a\) in front of the absolute value is:
Since \(a < 0\), the graph opens downwards. This eliminates the first graph, which opens upwards.
Calculate key points on the graph
We can find points on the graph by substituting \(x\)-values into the equation:
- For \(x = 2\):
So, the point \((2, -1)\) must be on the graph.
- For \(x = -2\):
So, the point \((-2, -1)\) must be on the graph.
Compare with the given options
Let's analyze the three graphs from left to right:
- First graph: Vertex is at \((0,0)\), opens upwards, and passes through \((1, 2)\). This represents \(y = 2|x|\).
- Second graph: Vertex is at \((0,0)\), opens downwards, and passes through \((2, -1)\) and \((-2, -1)\). This matches our calculated points.
- Third graph: Vertex is at \((0,0)\), opens downwards, and passes through \((1, -2)\) and \((-1, -2)\). This represents \(y = -2|x|\).
Therefore, the second graph is the correct representation.
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
- (A) The first graph (opens upwards with vertex at \((0,0)\) passing through \((1,2)\))
- (B) The second graph (opens downwards with vertex at \((0,0)\) passing through \((2,-1)\)) (Correct answer)
- (C) The third graph (opens downwards with vertex at \((0,0)\) passing through \((1,-2)\))