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Question
which expression is equivalent to \\(\frac{4a+4}{2a} \cdot \frac{a^2}{a+1}\\)?
\\(\frac{2(a+1)^2}{a^3}\\)
\\(6a\\)
\\(2a\\)
\\(\frac{6a^2}{a+1}\\)
Factor the numerators and denominators
$$
\frac{4a+4}{2a} \cdot \frac{a^2}{a+1} = \frac{4(a+1)}{2a} \cdot \frac{a^2}{a+1}
$$
Cancel common factors
$$
\frac{4(a+1) \cdot a^2}{2a(a+1)} = \frac{4}{2} \cdot \frac{a+1}{a+1} \cdot \frac{a^2}{a}
$$
Simplify the expression
$$
2 \cdot 1 \cdot a = 2a
$$
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- (A) \(\frac{2(a+1)^2}{a^3}\)
- (B) \(6a\)
- (C) \(2a\) (Correct answer)
- (D) \(\frac{6a^2}{a+1}\)