which equation has $x = 4$ as the solution?

$\log_{4}(3x+4) = 2$
$\log_{3}(2x-5) = 2$
$\log_{x}64 = 4$
$\log_{x}16 = 4$

Question

which equation has $x = 4$ as the solution?

$\log_{4}(3x+4) = 2$
$\log_{3}(2x-5) = 2$
$\log_{x}64 = 4$
$\log_{x}16 = 4$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Solving Logarithmic Equations" ], "new_concepts": [], "current_concepts": [ "Solving Logarithmic Equations", "Logarithmic Evaluation" ] } ## Test the first equation Using the *Solving Logarithmic Equations* knowledge point $$ \begin{aligned} &\log_4(3(4)+4) = \log_4(12+4) = \log_4(16)\ &\log_4(16) = 2 \end{aligned} $$ ## Test the second equation Using the *Solving Logarithmic Equations* knowledge point $$ \begin{aligned} &\log_3(2(4)-5) = \log_3(8-5) = \log_3(3)\ &\log_3(3) = 1 e 2 \end{aligned} $$ ## Test the third equation Using the *Solving Logarithmic Equations* knowledge point $$ \begin{aligned} &\log_4(64) = 3 e 4 \end{aligned} $$ ## Test the fourth equation Using the *Solving Logarithmic Equations* knowledge point $$ \begin{aligned} &\log_4(16) = 2 e 4 \end{aligned} $$

(A) $\log_4(3x+4)=2$

(B) $\log_3(2x-5)=2$

(C) $\log_x 64=4$

(D) $\log_x 16=4$

{ "subject": "Mathematics", "question_type": "Multiple Choice", "knowledge_point": [ "Mathematics", "Algebra", "Solving Logarithmic Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Test the first equation

Test the second equation

Test the third equation

Test the fourth equation

Answer: